I would suggest that you use a 'list' for the data. Something like
this should work:
objs <- grep("^mrunoff_", ls(), values=TRUE) # get the names of the objects
result <- lapply(objs, function(.obj){
.obj <- get(.obj) # get the value
lapply(1:12, function(. iter) .obj[,, .iter])
})
On Fri, Jan 22, 2010 at 11:32 AM, Steve Murray <smurray...@hotmail.com> wrote:
>
> Dear all,
>
> I have 30 arrays, each with dimensions 720,360,12. The naming format for each
> of these 30 objects is: mrunoff_5221, mrunoff_5222... mrunoff_5250.
>
>
> For example:
>> str(mrunoff_5221)
> num [1:720, 1:360, 1:12] NA NA NA NA NA NA NA NA NA NA ... (the initial
> NA's are nothing to worry about)
>
>
> I am looking for a way by which I can extract each of the third dimension of
> these grids (1:12) in turn, along with the first and second dimensions, to
> create new objects in the following style:
>
>
> #2071
> mrunoff_207101 <- mrunoff_5221[,,1]
> mrunoff_207102 <- mrunoff_5221[,,2]
> mrunoff_207103 <- mrunoff_5221[,,3]
> mrunoff_207104 <- mrunoff_5221[,,4]
> mrunoff_207105 <- mrunoff_5221[,,5] ...(etc. - up to [,,12])
>
> #2072
> mrunoff_207201 <- mrunoff_5222[,,1]
> mrunoff_207202 <- mrunoff_5222[,,2]
> mrunoff_207203 <- mrunoff_5222[,,3]
> mrunoff_207204 <- mrunoff_5222[,,4]
> mrunoff_207205 <- mrunoff_5222[,,5] ...(etc. - up to [,,12]) and mrunoff_
> continues to 2100 and 5250 respectively.
>
>
> Clearly, this is a cumbersome and non-sustainable way to proceed! There will
> be 360 new objects in total, and I imagine that there must be a more
> effective way of achieving this, either via a loop or, possibly, one of the
> 'apply' functions. Yet my attempts to date have so far resulted in... well, a
> complete mess!
>
> If anyone has any suggestions as to a more efficient means of achieving this,
> then I'd be very grateful to hear them.
>
> Many thanks,
>
> Steve
>
>
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--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
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