Thanks Baptiste, it does help.
However, I don't really understand what "[" means. Could you please tell
me more about it? I didn't find anything helpful on that in the help.
Thanks in advance
Ivan
Le 1/22/2010 17:19, baptiste auguie a écrit :
Hi,
Try this,
a = replicate(3, data.frame(x=1:10, y=rnorm(10)), simplify=FALSE)
lapply(a, "[", "y")
HTH,
baptiste
2010/1/22 Ivan Calandra<ivan.calan...@uni-hamburg.de>:
Hi everybody!
I have a (stupid) question but I cannot find a way to do it!
I have a list like:
SPECSHOR_tx_Asfc
$cotau
SPECSHOR Asfc.median
38 cotau 381.0247
39 cotau 154.6280
40 cotau 303.3219
41 cotau 351.2933
42 cotau 156.5327
$eqgre
SPECSHOR Asfc.median
145 eqgre 219.5389
146 eqgre 162.5926
147 eqgre 146.3726
148 eqgre 127.6413
149 eqgre 274.2888
$gicam
SPECSHOR Asfc.median
263 gicam 174.7445
264 gicam 83.4821
265 gicam 157.6005
266 gicam 153.7519
267 gicam 344.9775
I would just like to remove the column "SPECSHOR" (or extract the other one)
so that it looks like
$cotau
Asfc.median
38 381.0247
39 154.6280
40 303.3219
41 351.2933
42 156.5327
etc.
How should I do it? I know how to select each element like
SPECSHOR_tx_Asfc[[1]], but I don't know how to select a single column within
an element.
Could you please help me on that?
Thanks
Ivan
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--
Ivan CALANDRA
PhD Student
University of Hamburg
Biozentrum Grindel und Zoologisches Institut und Museum
Martin-Luther-King-Platz 3
D-20146 Hamburg, GERMANY
+49(0)40 42838 6231
ivan.calan...@uni-hamburg.de
**********
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