Hi: Per Baptiste's suggestion (not the iapply one, the plyr one :)
> aaply(b, 1, function(x) sort(x, na.last = FALSE)) Var1 1 2 3 4 5 6 1 1 2 4 5 7 9 2 NA 2 3 3 3 5 HTH, Dennis On Tue, Jan 19, 2010 at 2:27 AM, marco salvini <marco.salv...@gmail.com>wrote: > Can you please help on the issue? > I using the apply command on a matrix below the example: > > Create a vector > x =c(5, 3, 2:4, NA, 7, 3, 9, 2, 1, 5) > > create a matrix of 2 rows by 6 columns > b=matrix(x, 2,6) > print(b) > [,1] [,2] [,3] [,4] [,5] [,6] > [1,] 5 2 4 7 9 1 > [2,] 3 3 NA 3 2 5 > > using the command apply > print(apply(b, 1, function(y) sort(y, na.last=F))) > > the output is a matrix of 6 rows by 2 columns. > [,1] [,2] > [1,] 1 NA > [2,] 2 2 > [3,] 4 3 > [4,] 5 3 > [5,] 7 3 > [6,] 9 5 > > As you can see in the example I start with a matrix of (2 by 6) and the > output of apply is a mtraxi of (6 by 2). > This is very strange because I was expecting as output a matrix of the same > dim (2 by 6) of the input matrix. I can solve this issues using an if > statment on the dim of the matrix but if I am using a square matrix I am > not > able to control if the result of the apply is correct. > > Do anyone find a solution to this issue? > thanks > Marco > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
