Try this: class(mm) <- "numeric"
On Sun, Jan 17, 2010 at 5:17 PM, ivan popivanov <ivan.popiva...@hotmail.com> wrote: > > Hello, > > > > This turned out to be surprisingly hard for me: > > > > Let's say I have > > > > mm = matrix(as.character(seq(1,30, 1)), nrow=3); mm > > [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] > [1,] "1" "4" "7" "10" "13" "16" "19" "22" "25" "28" > [2,] "2" "5" "8" "11" "14" "17" "20" "23" "26" "29" > [3,] "3" "6" "9" "12" "15" "18" "21" "24" "27" "30" > > > > which is a matrix of strings, I'd like to convert this to a matrix of the > corresponding numbers: > > > > nn = matrix(seq(1,30, 1), nrow=3), nn > > [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] > [1,] 1 4 7 10 13 16 19 22 25 28 > [2,] 2 5 8 11 14 17 20 23 26 29 > [3,] 3 6 9 12 15 18 21 24 27 30 > > > > I can convert each dimension using sapply(mm[,1], as.numeric), but how to > convert the full matrix?! > > > > In fact I hit this problem because I got a data.frame consisting of factors > (numerics represented as strings) when I queried a database. So if you can > advise how to convert this data.frame to a data.frame with proper numerics - > that would be even better. The problem is that my numerics are doubles and > the data.matrix function seems to cast factors to ints. > > > > Thanks in advance, > > Ivan > > > > _________________________________________________________________ > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
