Try this:
transform(df, v = unlist(with(df, tapply(v, f, cumsum))))
On Fri, Jan 8, 2010 at 4:10 PM, Daniel Murphy <chiefmur...@gmail.com> wrote:
> When the 'by' function forms subsets, are the rows in the same order as they
> are in the original data frame?
>
> For example, I want to use 'by' to calculate cumulative sums of a value 'v'
> by date 'd' for different levels of a factor 'f':
>
>>
> df<-data.frame(f=c("A","A","B"),d=as.Date(c("2010-1-1","2010-2-1","2010-1-1")),v=c(100,200,150))
>> df
> f d v
> 1 A 2010-01-01 100
> 2 A 2010-02-01 200
> 3 B 2010-01-01 150
>> do.call(rbind,by(df,df$f,FUN=function(x)
> data.frame(x[1],x[2],cumsum(x[3]))))
> f d v
> A.1 A 2010-01-01 100
> A.2 A 2010-02-01 300
> B B 2010-01-01 150
>
> This is exactly what I want, namely, cumulative sums by date.
>
> Can I be sure that the rows within subset A will be arranged in date order
> as they are in the original data frame? I would not want 'by' to randomly
> switch the order and create, for example,
> f d v
> A.1 A 2010-02-01 200
> A.2 A 2010-01-01 300
> B B 2010-01-01 150
>
> I could force the order of each subset within the FUN of by, adding to the
> execution time. Would that be advised?
>
> Thanks,
>
> Dan
>
> [[alternative HTML version deleted]]
>
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--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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