Try this:
# same args as lapply. FUN must return named components.
lapplyWithRename <- function(...) {
x <- lapply(...)
names(x) <- sapply(x, names)
lapply(x, function(x) { names(x) <- NULL; x })
}
# test function - if x is "A" then f returns c("Name A" = "A")
f <- function(x) structure(x, .Names = paste("Name", x))
L <- list(a="A", b="B")
lapplyWithRename(L, f)
Output looks like this:
> lapplyWithRename(L, f)
$`Name A`
[1] "A"
$`Name B`
[1] "B"
On Fri, Jan 1, 2010 at 8:21 AM, Mark Heckmann <mark.heckm...@gmx.de> wrote:
> Happy New Year, all!
>
> I want to do calculations on each element of a list l, but i want the
> returned list element to be named differently after the calculation.
> Is it possible to do the renaming somehow within the lapply call?
>
> l <- list(a=NA, b=NA)
> lapply(l, function(x) {names(x) <- "new name"; return(x) })
>
> This does not work, any ideas?
> TIA
>
> –––––––––––––––––––––––––––––––––––––––
> Mark Heckmann
> Dipl. Wirt.-Ing. cand. Psych.
> Vorstraße 93 B01
> 28359 Bremen
> Blog: www.markheckmann.de
> R-Blog: http://ryouready.wordpress.com
>
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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>
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