The following code returns a list with the 2nd element as NULL. I'm
wondering what the best way to get rid of NULL element in an
'apply()'s result.
> lapply(1:3, function(x) {
+ if(x==2) {
+ return(NULL)
+ } else {
+ return(x)
+ }
+ }
+ )
[[1]]
[1] 1
[[2]]
NULL
[[3]]
[1] 3
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