On Tue, Dec 8, 2009 at 11:05 PM, David Winsemius <dwinsem...@comcast.net> wrote:
>
> On Dec 8, 2009, at 11:37 PM, Peng Yu wrote:
>
>> I want to split a matrix, where both 'u' and 'w' are results of
>> possible ways. However, whenever 'n' changes, the argument passed to
>> mapply() has to change. Is there a way to pass elements of a list as
>> multiple arguments?
>
> You need to explain what you want in more detail. In your example mapply did
> exactly what you told it to. No errors. Three matrices. What were you
> expecting when you gave it three lists in each argument?
I want a general solution so that I don't have to always write
"v[[1]], v[[2]], ..., v[[n]]" like in the following, because the
following way would not work if 'n' is an arbitrary number.
w=mapply(function(x,y) {cbind(x,y)}, v[[1]], v[[2]], ..., v[[n]])
One way that I can think of is to somehow expand a list (i.e., v in
this case) to a set of arguments that can be passed to 'mapply()'.
>> m=10
>> n=2
>> k=3
>>
>> set.seed(0)
>> x=replicate(n,rnorm(m))
>> f=sample(1:k, size=m, replace=T)
>>
>> u=split(as.data.frame(x),f)
>>
>> v=lapply(
>> 1:dim(x)[[2]]
>> , function(i) {
>> split(x[,i],f)
>> }
>> )
>>
>> w=mapply(
>> function(x,y) {
>> cbind(x,y)
>> }
>> , v[[1]], v[[2]]
>> )
>
> --
>
> David Winsemius, MD
> Heritage Laboratories
> West Hartford, CT
>
>
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