Yes... It assing to each list component the index... As you see I want to modify each component of the list so I can use it at the following step o the lapply procedure.
El mié, 02-12-2009 a las 17:23 -0200, Henrique Dallazuanna escribió: > Try this: > > z1[] <- 1:3 > > > > On Wed, Dec 2, 2009 at 5:17 PM, Kenneth Roy Cabrera Torres > <krcab...@une.net.co> wrote: > > Hi R users: > > > > I got an error that "l1" is not found. > > > > This is a sample code: > > > > f1<-function(i,l1){ > > print(l1[[i]]) > > l1[[i+1]]<<-i > > return(i) > > } > > > > z1<-list(x=100,NULL,a=c(1,1)) > > lapply(1:3,f1,l1=z1) > > > > My final goal is to update the value of > > each list component to use it in the following > > step. > > > > I see that print function founds l1[[1]], > > but the assign instruction not. > > > > Thank you for your help. > > > > Kenneth > > > > PD: R.Version()$version.string > > [1] "R version 2.10.0 Patched (2009-11-24 r50556)" > > on Ubuntu linux. > > > > ______________________________________________ > > R-help@r-project.org mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > > > > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.