On Dec 2, 2009, at 12:18 PM, Mark Heckmann wrote:

I have a vector and need to count how many data points fall inside each bin:

dat <- rnorm(100)
breaks <- -3:3
table((cut(dat, breaks)))

(-3,-2] (-2,-1]  (-1,0]   (0,1]   (1,2]   (2,3]
     3      13      42      30      12       0

if I reverse the breaks vector, the results remains the same:
breaks <- rev(breaks)
table((cut(dat, breaks)))

(-3,-2] (-2,-1]  (-1,0]   (0,1]   (1,2]   (2,3]
     3      13      42      30      12       0

What I would like is break to also determine the order of the table output, in this case it should also be reversed, like:

Instead of reversing the breaks (which doesn't work because factors obey a very strange physics) reverse the table:

> rev(table((cut(dat, breaks))))

  (2,3]   (1,2]   (0,1]  (-1,0] (-2,-1] (-3,-2]
      2      21      25      35      14       3


( 3, 2] ( 2, 1]  ( 1,0]   (0,-1]   (-1,-2]   (-2,-3]
     0      12      30      42      13       3

Thus I would like to reorder the vector using break, but I do not know how.

TIA
Mark
–––––––––––––––––––––––––––––––––––––––
Mark Heckmann
Dipl. Wirt.-Ing. cand. Psych.
Vorstraße 93 B01
28359 Bremen
Blog: www.markheckmann.de
R-Blog: http://ryouready.wordpress.com

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David Winsemius, MD
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