On Dec 1, 2009, at 10:59 PM, jim holtman wrote:

The factor statement should have been: (missed the 'vec' on the first reading)

dataDF$A1 <- factor(dataDF$A1, levels=vec)

It's not necessary to alter the data.frame. You can use the results of the construction above as the row index and still keep the original order:

> dataDF[factor(dataDF$A1, levels=vec), ]
  A1 A2
3  C  3
2  A  2
1  B  1

> dataDF
  A1 A2
1  B  1
2  A  2
3  C  3

--
David.

On Tue, Dec 1, 2009 at 10:57 PM, jim holtman <jholt...@gmail.com> wrote:
Is this what you want:

dataDF = data.frame(A1 = c("B", "A", "C"), A2 = c(1,2,3))
dataDF
 A1 A2
1  B  1
2  A  2
3  C  3
dataDF[order(dataDF$A1),]
 A1 A2
2  A  2
1  B  1
3  C  3


If you want the sequence "CAB" then you will have to change the
factors in column 1:

dataDF$A1 <- factor(dataDF$A1, levels=c("C", "A", "B"))
dataDF[order(dataDF$A1),]
 A1 A2
3  C  3
2  A  2
1  B  1



On Tue, Dec 1, 2009 at 10:36 PM, Hao Cen <h...@andrew.cmu.edu> wrote:
Hi,



I have a a vector  and a data frame with two columns

vec = c("C", "A", "B")

dataDF = data.frame(A1 = c("B", "A", "C"), A2 = c(1,2,3))



I would like to sort the data frame by column A1 such that the order of
elements in A1 is as the same as in vec.



After the ordering, the data frame would be

A1           A2

C             3

A             2

B             1



Any suggestions would be appreciated.



Thanks in advance



Jeff


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--
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?




--
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?

______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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