Or maybe aperm() is faster:
max(colSums(aperm(yourArray, c(2,1,3))))
-Peter Ehlers
Peter Ehlers wrote:
Does this
max(apply(yourArray, 3, rowSums))
give you what you want?
-Peter Ehlers
Will Carr wrote:
Working with an NxMxO sized matrix, currently I can do this in my code:
if (max(colSums(array)) >= number)
But to get an equivalent result using rowSums, I have to do:
for (i in 1:10)
{
if (max(rowSums(array[,,i])) >= number) }
I'm running both in a much larger loop that loops millions of times, so
speed and such is quite a big factor for me. Currently, the colSums line
uses about 1/10th as much time as the rowSums' for loop, and the for loop
actually took as much time as the rest of my code combined took to
execute.
Is there a faster way than using a for loop and rowSums?
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