Thanks very much. Using the matrix function and then DF[,ix] gives me exactly what I wanted. Jabez
--- On Wed, 25/11/09, Gabor Grothendieck <ggrothendi...@gmail.com> wrote: From: Gabor Grothendieck <ggrothendi...@gmail.com> Subject: Re: [R] Re-arrange Columns in data frame To: "Jabez Wilson" <jabez...@yahoo.co.uk> Cc: "R Mailing List" <r-help@r-project.org> Date: Wednesday, 25 November, 2009, 16:27 Try this: # first case ix <- c(matrix(1:24, 4, byrow = TRUE)) DF[ix] # second case ix <- c(matrix(1:16, 4, byrow = TRUE)) DF[ix] On Wed, Nov 25, 2009 at 11:16 AM, Jabez Wilson <jabez...@yahoo.co.uk> wrote: > Hi, I have a data frame which is 24 columns by 10 rows. This is essentially > 6 groups of 4 columns. I want to re-arrange the columns into the following > order 1,7,13,19,2,8,14,20,3,9,15,21,4,10,16,22,5,11,17,23,6,12,18,24 i.e. > first of each group of 6 grouped together, then 2nd of each group of six etc. > I know that I can do > df[,c(1,7,13,19,2,8,14,20,3,9,15,21,4,10,16,22,5,11,17,23,6,12,18,24)], but > what if I now have 4 groups of 4 columns, I would want the order to be > c(1,5,9,13,2,6,10,14,3,7,11,15,4,8,12,16). I know that seq() comes into it > somewhere, and I've got as far as seq(1,ncol(df),number_of_groups), but that > gives me only one sequence. Is there a way of combining with rep() that can > do this? > Jabez > > > > [[alternative HTML version deleted]] > > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > [[alternative HTML version deleted]]
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
