On Nov 24, 2009, at 2:24 PM, Andreas Wittmann wrote:

Dear R-users,

in the follwing thread

http://tolstoy.newcastle.edu.au/R/help/03b/3322.html

the problem how to remove rows for predict that contain levels which are not in the model.

now i try to do this the other way round and want to remove columns (variables) in the model which will be later problematic with new levels for prediction.

## example:
set.seed(0)
x <- rnorm(9)
y <- x + rnorm(9)

training <- data.frame(x=x, y=y, z=c(rep("A", 3), rep("B", 3), rep("C", 3)))
test <- data.frame(x=t<-rnorm(1), y=t+rnorm(1), z="D")

lm1 <- lm(x ~ ., data=training)
## prediction does not work because the variable z has the new level "D"
predict(lm1, test)

## solution: the variable z is removed from the model
## the prediction happens without using the information of variable z
lm2 <- lm(x ~ y, data=training)
predict(lm2, test)

How can i autmatically recognice this and calculate according to this?

Let me get this straight. You want us to predict in advance (or more accurately design an algorithm that can see into the future and work around) any sort of newdata you might later construct????

--

David Winsemius, MD
Heritage Laboratories
West Hartford, CT

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to