tsp is supposed to be applied to a ts object. If you are not using ts objects then that is your problem.
On Fri, Nov 20, 2009 at 6:43 PM, Samik Raychaudhuri <sam...@gmail.com> wrote: > Looks like there is a difference between when I use frequency(x) vs. when I > use frequency(x.ts). If I try to get the tsp attribute of x by using attr(x, > "tsp"), it still shows up as NULL. When I looked at the code of frequency() > function (in stats), it seems to be looking at attr(x, "tsp"), which is > NULL, so the function returns 1. > Let me relate the context a bit. I am trying to use the function > forecast:nsdiffs to perform a Canova-Hansen test for a given dataset. Even > though I specify the seasonality, in an internal function, frequency(x) is > used to find seasonality, and since that value is 1 (as I explained above: > it looks at attr(x, "tsp")), the calculations do not succeed. > > On 11/20/2009 4:25 PM, Gabor Grothendieck wrote: >> >> Not for me. >> >> >>> >>> x <- 1:100 >>> x.ts <- ts(x, start = 1, frequency = 4) >>> frequency(x.ts) >>> >> >> [1] 4 >> >> >> >> > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
