try this:
> x <- ' middle of the string '
> sub("^[[:space:]]*(.*?)[[:space:]]*$", "\\1", x, perl=TRUE)
[1] "middle of the string"
On Fri, Nov 20, 2009 at 10:51 AM, Bos, Roger <roger....@rothschild.com> wrote:
> I have a character string and I would like to remove the leading and
> tailing white spaces. The example for 'sub' shows how to remove the
> trailing white spaces, but I still can't figure out how to remove both
> trailing and leading white spaces because I can't find any documentation
> for what "+$" means or what "\\s+$" means. Maybe its because I don't
> have a Unix background. Thanks in advance for any help with this.
>
> str <- ' Now is the time '
> sub(' +$', '', str) ## spaces only
> sub('[[:space:]]+$', '', str) ## white space, POSIX-style
> sub('\\s+$', '', str, perl = TRUE) ## Perl-style white space
>
> Thanks,
>
> Roger
> ***************************************************************
>
> This message is for the named person's use only. It may\...{{dropped:23}}
>
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>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
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