coef(summary(fit_cox)) should give you what you wanted. Regards, Yihui -- Yihui Xie <xieyi...@gmail.com> Phone: 515-294-6609 Web: http://yihui.name Department of Statistics, Iowa State University 3211 Snedecor Hall, Ames, IA
On Tue, Nov 3, 2009 at 12:31 AM, 孟欣 <lm_meng...@163.com> wrote: > Hi all: > I finished cox analysis like this: > fit_cox<-coxph(Surv(dat$Time, dat$death) ~ dat$CD4 + > strata(dat$gender),data=dat); >> fit_cox > Call: > coxph(formula = Surv(data_ori$Time, data_ori$death) ~ data_ori$drug + > strata(data_ori$gender), data = data_ori) > > coef exp(coef) se(coef) z p > data_ori$drugddI 0.216 1.24 0.146 1.47 0.14 > Likelihood ratio test=2.17 on 1 df, p=0.140 n= 467 > > I wanna extract the result: > 0.216 1.24 0.146 1.47 0.14 and the corresponding name "coef exp(coef) > se(coef) z p" > from fit_cox. > > I use the command: > str(fit_cox),but I can only find 0.216 of the result,but the other four > results( 1.24 0.146 1.47 0.14) can't be found. > > > Anyone can help me? > Thanks a lot! ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
