On Nov 2, 2009, at 2:49 PM, Jorge Ivan Velez wrote:
Hi Ashta,
Yes, it is possible. Here is a suggestion:
# Data set
x <- read.table(textConnection("v1 v2 v3 v4
5 6 9 10
3 4 7 10
4 6 10 18"), header = TRUE)
closeAllConnections()
# Table
res <- table(data.matrix(x))
f <- sort(res, decreasing = TRUE)
data.frame(value = names(f), counts = f)
# :-)
require(fortunes)
fortune('Only how')
HTH,
Jorge
On Mon, Nov 2, 2009 at 2:26 PM, Ashta <> wrote:
Thank you Jorge and
# 10 4 6 3 5 7 9 18
# 3 2 2 1 1 1 1 1
This one works fine for me. Is it possible to transpose it?
I tried t(res[order(res, decreasing = TRUE)]), but it did not work!
And in the spirit of that fortune above, also look at:
t(t(res[order(res, decreasing = TRUE)]))
The extra t() coerces to a matrix and the outer t() does the transpose
(I think).
--
David.
I want the result like this
10 2
4 2
6 2
3 1
. .
. .
On Mon, Nov 2, 2009 at 1:45 PM, Jorge Ivan Velez
<> wrote:
Hi Val,
Here is a suggestion:
res <- table(unlist(x))
res[order(res, decreasing = TRUE)]
# 10 4 6 3 5 7 9 18
# 3 2 2 1 1 1 1 1
HTH,
Jorge
On Mon, Nov 2, 2009 at 1:35 PM, Val <> wrote:
BAYESIAN INFERENCES FOR MILKING TEMPERAMENT IN CANADIAN HOLSTEINS
Hi All,
I have a data set "x" with several variables. Sample of the
data is
shown
below
V1 v2 v3 v4
5 6 9 10
3 4 7 10
4 6 10 18
I want the frequency of each data point sorted by their
occurrence.
Below is the output that I want
10 =3
6=2
4=2
9=1
5=1
7=1
3=1
How do I do it in R?
Thanks in advance
Val
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______________________________________________
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PLEASE do read the posting guide
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______________________________________________
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.