Hi Rafael, Here is a suggestion:
# Data pos <- c(27/44, 11/32, 8/40, 4/42, 3/40, 4/40, 2/40) tmin <- c(15.8, 12.6, 10.5, 2.4, 5.2, 8.5, 7.9) d <- data.frame(pos, tmin) # Non-linear model fit <- nls(pos ~ a*tmin^b, data = d, start = list(a = .1, b = .1), trace = TRUE) summary(fit) # Plot res <- data.frame(tmin, pred = predict(fit)) plot(tmin, pos, ylim = c(0,.7)) points(res[order(tmin),], type='l', col=2) See ?nls for more details and information. Also, take a look at ?glm and its examples for poisson and logistic regression. Best regards, Jorge On Mon, Oct 26, 2009 at 1:44 PM, Rafael Moral <> wrote: > Dear useRs, > > I have the following plot: > > > pos <- c(27/44, 11/32, 8/40, 4/42, 3/40, 4/40, 2/40) > tmin <- c(15.8, 12.6, 10.5, 2.4, 5.2, 8.5, 7.9) > plot(tmin, pos) > > > I would like to fit an exponential curve to it. > How could I be able to do this? > > Thanks in advance, > > Rafael. > > > > > ____________________________________________________________________________________ > [[elided Yahoo spam]] > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.