do you mean:
f <- factor(c("pigs", "pigs", "slugs"))
jj <- list(pigs = 1:10, slugs = 1:3)
jj[levels(f)[1]]
jj[[levels(f)[1]]]
Best,
Dimitris
Robin Hankin wrote:
Hi
I have a factor 'f' and a named list 'jj'.
I want names(jj) to match up with levels(f).
How do I use levels(f) to access elements of jj?
> f <- factor(c("pigs","pigs","slugs"))
> f
[1] pigs pigs slugs
Levels: pigs slugs
>
> jj <- list(pigs=1:10,slugs=1:3)
My attempts to produce jj$pigs all give errors:
> jj$levels(f)[1]
Error: attempt to apply non-function
> do.call("$",jj,levels(f)[1])
Error in if (quote) { : argument is not interpretable as logical
> "$"(jj,levels(f)[1])
Error in jj$levels(f)[1] : invalid subscript type 'language'
--
Dimitris Rizopoulos
Assistant Professor
Department of Biostatistics
Erasmus University Medical Center
Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands
Tel: +31/(0)10/7043478
Fax: +31/(0)10/7043014
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