I just quickly draft one with boston housing data. and it should be close to what you need.
# REMOVE ALL OBJECTS rm(list = ls()); # DATA PREPARATION library(MASS); data(Boston); X<-I(as.matrix(Boston[-14])); Y<-I(as.matrix(Boston[14])); for(i in 1:13) { X2 <- X[, i] data <- data.frame(Y, X2) lm<-glm(Y~X, data = data) name<-paste("glm", i, sep = ""); assign(name, lm); }; # LIST ALL OBJECTS WITH "glm" IN THE NAMES ls(pat = "glm"); On Sun, Sep 20, 2009 at 2:05 PM, Georg Ehret <georgeh...@gmail.com> wrote: > Dear R community, > I have a dataframe with say 100 different variables. I wish to regress > variable 1 separately on every other variable (2-100) in a linear regression > using lm. There must be an easy way to do this without loops, but I have > difficulties figuring this out... Can you please help? > Thank you and best regards, Georg. > ***************************************** > Georg Ehret > Johns Hopkins University > Institute of Genetic Medicine > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- ============================== WenSui Liu Blog : statcompute.spaces.live.com Tough Times Never Last. But Tough People Do. - Robert Schuller ============================== ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.