Presumably there is no reason to attempt plotting an empty column, so best approach is probably to remove the columns that contain no values.
Try > f.temp<-f[,-which(apply(f,2,function(x)all(is.na(x))))] and then run your script for f.temp instead of the original f. Also, you may find you have to use > min(x, na.rm=T) instead of just > min(x) for any other columns that contain NA values as well as real values. Chris Li wrote: > > Hi all, > > I have got a dataset like the following: > > a b c > 1 5 > 2 > 3 7 > > I am taking the minimum of each column and use it as the minimum of the > y-axis of my graphs. My scripts (simplified version) are like the > following: > > f<-array > f[1]=a > f[2]=b > f[3]=c > for i in 1:3 > name=f[i] > ymin<-min(dataset$f[i]) > plot(x,y,ylim=c(ymin,100)) > > The script stops at b, because the min function returns inf value. What > can I do to overcome it? > > Many thanks, > Chris > -- View this message in context: http://www.nabble.com/How-to-calculate-min-of-a-dataset-that-contains-empty-column-tp25463449p25466916.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
