Try this: data2[order(data2[,2], match(data2[,1], tolower(month.abb))),]
On Fri, Sep 11, 2009 at 10:46 AM, megh <megh700...@yahoo.com> wrote: > > I have following object : > > > date2 > [,1] [,2] > [1,] "apr" "1992" > [2,] "aug" "1992" > [3,] "dec" "1992" > [4,] "feb" "1992" > [5,] "jan" "1992" > [6,] "jul" "1992" > [7,] "jun" "1992" > [8,] "mar" "1992" > [9,] "may" "1992" > [10,] "nov" "1992" > [11,] "oct" "1992" > [12,] "sep" "1992" > [13,] "apr" "1993" > [14,] "aug" "1993" > [15,] "dec" "1993" > [16,] "feb" "1993" > [17,] "jan" "1993" > [18,] "jul" "1993" > [19,] "jun" "1993" > [20,] "mar" "1993" > [21,] "may" "1993" > [22,] "nov" "1993" > [23,] "oct" "1993" > [24,] "sep" "1993" > [25,] "apr" "1994" > [26,] "aug" "1994" > [27,] "dec" "1994" > [28,] "feb" "1994" > [29,] "jan" "1994" > [30,] "jul" "1994" > > Now I want to sort the elements like below, and want to get the index > numbers of "date2" under following sorting scheme. > > "jan" "1992" > "feb" "1992" > "mar" "1992" > ............ > "dec" "1992" > "jan" "1993" > "feb" "1993" > "mar" "1993" > ............ > "dec" "1993" > "jan" "1994" > "feb" "1994" > "mar" "1994" > ............ > "dec" "1994" > > Can anyone help me please? > -- > View this message in context: > http://www.nabble.com/Sorting-tp25401249p25401249.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O [[alternative HTML version deleted]]
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
