It depends. If there are patterns in the names, you can make use of pattern argument of ls(). For example, > x1="a";x2="b";x3="c" > ls(pattern="x[1-2]") [1] "x1" "x2" > ls(pattern="x[^1-2]") [1] "x3" # to remove x1-x3 >rm(list=ls(pattern="x[1-2]"))
More generally, if you want to remove all butx,xx,xxx, you can use >rm(list=ls()[! ls() %in% c(x,xx,xxx)]) Hope this helps. 2009/8/25 Steven Kang <stochastick...@gmail.com>: > Hi all, > > I am currently woking with hundreds of objects in workspace and whenever I > invoke ls() to observe the names of the objects, there are too much of > unnecessary variables. > > For example, if I only require say 3 or 4 objects from hundreds of objects > in workspace, are there any methods that may do the job? > > I have tried rm(-c(x,xx,xxx)), but no luck.. > > Your feedback in this problem would be highly appreciated. > > > > > > Steve > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- HUANG Ronggui, Wincent PhD Candidate Dept of Public and Social Administration City University of Hong Kong Home page: http://asrr.r-forge.r-project.org/rghuang.html ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
