Hi gregorio,

I think you can have nested for() without problem, like:
for (i in sth : sth[length(sth)])
   {
   for (k in A:B)
      {
      ....
      }
   }

or you can build conditional for's like:

rangeNegative<-1:10
rangePositive<-1:20
if (rnorm(1)>=0) MYRANGE<-rangePositive
if (rnorm(1)<0)  MYRANGE<-rangeNegative
MYRANGE
for (i in MYRANGE)
   {

   }

I not played with the second question.

Good luck

milton
On Sun, Aug 23, 2009 at 4:34 PM, Grzes <gregori...@gmail.com> wrote:

>
> Hi,
> My english isn't briliant and my problem is very dificult to descripe but I
> try ;)
> My first question is: May I write loop "for" like this or similar - for (i
> in sth : sth[length(sth)],  k in sth else : length(sth else) ) -  I'd like
> to have two independent conditions in the same loop "for".
>
> My secound question depend on program below. I'd like to write every result
> in matrix but I also want to call my function "odleg" use vector "e3" -
> exactly using values which are inside.
>
> Can anyone please guide me, how to do that?
> Thanks
>
> ## Function
> odleg <- function (Xa,Xb,Ya,Yb){
> d <- ((Xa-Xb)^2+(Ya-Yb)^2)^(1/2)
> return (d)
> }
>
> # Database
> ma=matrix(c(0.51139630,-0.12937287, 0.19530080,
>
> 0.02273691,-0.43634186,-0.01717149,-0.27597035,-0.41732933,-0.15476464,-0.15692965),nrow
> = 5, ncol=2)
>
> e3<- c(1,2,4)
> for (i in e3[1] : e3[length(e3)]; (k in 1 : length(e3))){
> for (j in e3[1] : e3[length(e3)]; (l in 1 : length(e3))){
>
> me1[k,l] = odleg
>
> (nepitabds$points[i,1],nepitabds$points[j,1],nepitabds$points[i,2],nepitabds$points[j,2])
> }}
> --
> View this message in context:
> http://www.nabble.com/dificult-loop-%22for%22-tp25107157p25107157.html
> Sent from the R help mailing list archive at Nabble.com.
>
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