Try this, mystr <-"c==1" subset(foo, eval(parse(text = mystr)) )
library(fortunes) fortune("parse") # try several times # I prefer this, but there is probably a better way mycond<- quote(c==1) subset(foo, eval(bquote(.(mycond))) ) HTH, baptiste 2009/8/21 Sebastien Bihorel <sebastien.biho...@cognigencorp.com>: > Dear R-users, > > The following question bothered me for the whole afternoon: how can one pass > a string as the conditioning argument to subset? I tried plain mystr, > eval(mystr), expression(mystr), etc... I don't to be able to find the > correct syntax > >> foo <- data.frame(a=1:10,b=10:1,c=rep(1:2,5)) >> mystr<-"c==1" >> subset(foo,c==1) > a b c > 1 1 10 1 > 3 3 8 1 > 5 5 6 1 > 7 7 4 1 > 9 9 2 1 >> subset(foo,mystr) > Error in subset.data.frame(foo, mystr) : > 'subset' must evaluate to logical > > > > Any help would be greatly appreciated. > > Sebastien > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- _____________________________ Baptiste Auguié School of Physics University of Exeter Stocker Road, Exeter, Devon, EX4 4QL, UK http://newton.ex.ac.uk/research/emag ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.