Here is a second solution that may be closer to
what you were thinking of in terms of structure:
library(gsubfn)
gsubfn("[[:punct:]]", ~ sub("[^,]", "", x), string)
This matches each punctuation character and then
removes any non-commas by applying the
function function(x)sub("[^,]", "", x)
gsubfn is just like gsub except the replacement
string can be a replacement function and one
can abbreviate the function using a formula
notation as shown.
See http://gsubfn.googlecode.com
On Thu, Aug 6, 2009 at 11:00 AM, Gabor
Grothendieck<ggrothendi...@gmail.com> wrote:
> Try something along these lines:
>
> gsub("[^[:alnum:][:space:],]", "", string)
>
>
> On Thu, Aug 6, 2009 at 8:37 AM, Rnewbie<xua...@yahoo.com> wrote:
>>
>> Dear all,
>>
>> I wanted to remove all punctuations except commas from a string.
>>
>> I used:
>>
>> gsub("[[:punct:]]", "", string)
>>
>> but I don't know how to exclude the commas ",". Anyone would kindly answer
>> my basic question?
>> --
>> View this message in context:
>> http://www.nabble.com/Remove-all-punctuations-except-commas-tp24845721p24845721.html
>> Sent from the R help mailing list archive at Nabble.com.
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
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