Thank you
Gabor Grothendieck <ggrothendi...@gmail.com> napsal dne 29.07.2009
15:20:40:
> Here are a couple of possibilities:
>
> sub(".*\\.", "", s)
This seems to be the target. Can you be so kind and translate for me what
it really does?
".* matches several dots?
\\. what is this?
I thought sub finds a match and replaces "replacement" in a string. But
from this solution it seems that the command replaces all characters in a
string with empty string and leave only value after three or two dots? Am
I right?
Best regards
Petr
>
> library(gsubfn)
> strapply(s, "[0-9]*$", simplify = c)
>
>
>
> On Wed, Jul 29, 2009 at 9:10 AM, Petr PIKAL<petr.pi...@precheza.cz>
wrote:
> > Hi all
> >
> > I have got something like that (actually those are column names)
> >
> > [51] "X19.2.300b...80" "X19.2.400v...80" "X19.2.400b...80"
> > "X19.2.300v...90" "X19.2.300b...90"
> > [56] "X19.2.400v...90" "X19.2..400b..90" "X19.2.300v...100"
> > "X19.2.300b...100" "X19.2.400v...100"
> >
> > in character vector. I would like to get last n figures from this
> > character vector but my regexpr unerstanding is inferior and I did not
> > succeed.
> > Please, is there anybody who can extract those n digits from end of
each
> > character string? If there were only 2 digits I could use substr but
there
> > can be one, two or three digits.
> >
> > I tried several variations of
> >
> > gsub("0:9$", "\\1" ,names(foto)[10])
> >
> > but either got whole string or an error.
> >
> > Best regards
> > Petr
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
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