I tried searching but I couldn't quite find what I was looking for.
Here's a dummy data matrix (with row and column labels): > y 0 1 2 3 4 21 3 4 8 5 5 22 3 6 8 6 NA 23 4 5 11 4 3 24 4 2 1 4 6 25 6 4 4 6 6 I can get cumulative row sums as follows: > cy<-t(apply(y,1,cumsum)) > cy 0 1 2 3 4 21 3 7 15 20 25 22 3 9 17 23 NA 23 4 9 20 24 27 24 4 6 7 11 17 25 6 10 14 20 26 Which works, but this seems rather clumsy, especially the need for t(). Is there a better way? One that still retains row and/or column labels? (that will also work for data frames, if possible - though of course one can always as.data.frame() ) Row differences present a different problem. Here's one way to get back the original data: > cbind(cy[,1],cy[,-1]-cy[,-nrow(cy)]) 1 2 3 4 21 3 4 8 5 5 22 3 6 8 6 NA 23 4 5 11 4 3 24 4 2 1 4 6 25 6 4 4 6 6 However, if I use that I lose the first column label. Is there a way to do something like this without losing that label? (again, if possible, that also works for data frames?) thanks! Glen_B. -- View this message in context: http://www.nabble.com/Cumulative-row-sums%2C-row-differences-tp24692986p24692986.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.