It looks like a data.frame to me. Try str(psd) or class(psd) to check. Typeof
returns "list" for a data.frame since "data.frame" apparently is a subset of
"list". The 'months' that you are seeing are simply the rownames which by
chance are the same as the months.
I's suggest adding the months to the data.frame and then plotting
psd <- xx
psd[,4] <- 1:12
names(psd)[4] <- "months"
plot(sd~months, data=psd)
--- On Tue, 7/21/09, Graves, Gregory <ggra...@sfwmd.gov> wrote:
> From: Graves, Gregory <ggra...@sfwmd.gov>
> Subject: [R] how to use a list to create a plot
> To: r-help@r-project.org
> Received: Tuesday, July 21, 2009, 8:20 AM
> I issued the following command to
> obtain the std dev for each month.
>
>
>
> psd<-numSummary(Sal, groups=month, statistics=c("sd"))
>
>
>
> which resulted in
>
>
>
> > psd
>
>
> sd
> n
> NA
>
> 1
> 6.930340
> 9367 2319
>
> 2
> 7.847003
> 10827 1008
>
> 3
> 5.962308
> 12988 404
>
> 4
> 3.632105
> 12576 384
>
> 5
> 3.328189
> 13030 362
>
> 6
> 10.101336
> 12955 5
>
> 7
> 11.759585
> 13071 321
>
> 8
> 10.277566 12286
> 1105
>
> 9
> 8.561922
> 12286 674
>
> 10
> 9.252890
> 13343 27
>
> 11
> 9.568852
> 12591 369
>
> 12
> 9.622851
> 12020 946
>
>
>
> > typeof(psd)
>
> [1] "list"
>
>
>
> I want plot sd versus column 1 (month of year) of the list
> psd.
>
>
>
> The only way I can figure out how to do this is to manually
> copy the
> table into Excel, reformat, and then export that back out
> as a new csv.
> There has to be a better way?
>
>
>
>
>
> Gregory A. Graves
>
> Lead Scientist
>
> REstoration COoordination and VERification (RECOVER)
>
> Watershed Division
>
> South Florida Water Management District
>
> Phones: DESK: 561 / 682 - 2429
>
>
> CELL: 561 / 719 - 8157
>
>
>
>
>
>
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained,
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>
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