Here is a variation on the solution below (first line
is the same but second differs):
> ind <- which(a == 0, arr = TRUE)
> mapply("[", dimnames(a), as.data.frame(ind))
[,1] [,2]
[1,] "A1" "F1"
[2,] "A3" "F1"
[3,] "A2" "F2"
[4,] "A3" "F3"
On Thu, Jul 16, 2009 at 12:40 AM, Jorge Ivan
Velez<jorgeivanve...@gmail.com> wrote:
> Dear Alberto,
> Try this:
>
> # colnames and rownames
> cn <- colnames(a)
> rn <- rownames(a)
>
> # the index
> ind <- which(a==0, arr = TRUE)
>
> # the result
> data.frame( res = apply(ind, 1, function(x)
> paste(rn[x[1]],",", cn[x[2]], sep ="")
> )
> )
>
> # res
> # 1 A1,F1
> # 2 A3,F1
> # 3 A2,F2
> # 4 A3,F3
>
> See ?which, ?apply and ?paste for more information.
>
> HTH,
>
> Jorge
>
>
> On Wed, Jul 15, 2009 at 7:15 PM, Alberto Lora M <albertolo...@gmail.com>wrote:
>
>> Dear sir,
>>
>> I have a matrix like
>>
>> a<-matrix(c(0,2,0,4,0,6,5,8,0),nrow=3)
>> colnames(a)<-c("F1","F2","F3")
>> rownames(a)<-c("A1","A2","A3")
>> a
>>
>> F1 F2 F3
>> A1 0 4 5
>> A2 2 0 8
>> A3 0 6 0
>>
>> I want to extract all pairs (rownames, columnames) from which the value in
>> the matrix is 0
>>
>> The result should be something like this
>>
>> A1, F1
>> A2, F2
>> A3, F1
>> A3, F3
>>
>> how it is possible?
>>
>> thanks for your help....
>>
>> Best Regards
>>
>> Alberto
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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and provide commented, minimal, self-contained, reproducible code.
