Cvandy, is this close to what you need:

  > printT <- function ( .seq = seq ( 2 , 10 , 2 ) ) {
  +   x <- t ( sapply ( .seq , T , Lc ) )
  +   x <- cbind (
  +     .seq
  +     , rbind (
  +       format ( x [ 1 , ] * 100 )
  +       , format ( x [ -1 , ] , digits = 3 )
  +     )
  +   )
  +   dimnames ( x ) [[2]] <- NULL
  +   print ( x , quote = FALSE )
  + }
  > printT ( )
       [,1] [,2]  [,3]  [,4]  [,5]  [,6]  [,7]
  [1,] 2    70    75    80    85    90    95
  [2,] 4    0.490 0.562 0.640 0.722 0.810 0.902
  [3,] 6    0.398 0.475 0.562 0.657 0.762 0.876
  [4,] 8    0.343 0.422 0.512 0.614 0.729 0.857
  [5,] 10   0.306 0.385 0.477 0.583 0.705 0.843

Im not really sure what you mean by "Line up the first row with
the factors (decimal fractions)".

--
 David
 
 -----------------------------------------------------
 David Huffer, Ph.D.               Senior Statistician
 CSOSA/Washington, DC           david.huf...@csosa.gov
 -----------------------------------------------------


-----Original Message-----
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On 
Behalf Of cvandy
Sent: Wednesday, July 08, 2009 9:21 AM
To: r-help@r-project.org
Subject: [R] Formatting a Table


I've created a short program to print a table of learning curve factors. 
However, I cannot figure out how to format the table to:
1) Get rid of the [1]s in the first column and replace it with the values of
N.
2) Line up the first row with the factors (decimal fractions).
Thanks for any help.
The complete program and output is as follows:

> Lc<-seq(0.70,0.95,0.05) #Specify learning curves
> T<-function(N,Lc)  #Create a function to calc.time for Nth unit
+ {
+ N^(log(Lc,10)/log(2,10))  #Function
+ }
> for (N in seq(2,10,2))
+ {if (N==2){print(T(N,Lc)*100)}else{print(T(N,Lc),digits=3)}}
[1] 70 75 80 85 90 95
[1] 0.490 0.562 0.640 0.722 0.810 0.902
[1] 0.398 0.475 0.562 0.657 0.762 0.876
[1] 0.343 0.422 0.512 0.614 0.729 0.857
[1] 0.306 0.385 0.477 0.583 0.705 0.843
>
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