I looked at the question and Gabor's reply and could not figure out
why you were not simply replacing the function list() for head() in
the second line of his example. Or perhaps you were, and the result
was not what you wanted, in which case it would be of you not being
clear about the desired output. Either way a response seemed
unwarranted.
--
DW
On Jul 4, 2009, at 2:51 AM, Bogaso wrote:
No reply yet. Is my question not clear? Please let me know.
Thanks
Bogaso wrote:
Thanks Gabor for this reply. However can please clarify one more
thing?
How I want to create a list,
wherein each member of that list is the monthly observations. For
example,
1st member of list contains daily observation of 1st month, 2nd
member
contains daily observation of 2nd month etc.
Thanks
Gabor Grothendieck wrote:
Try this:
z <- zooreg(1:365, start = as.Date("2001-01-01"), freq = 1)
f <- head
tapply(seq_along(z), as.yearmon(time(z)), function(ix) f(z[ix]))
where you should replace f with a function that does whatever
you want with each month's data. Here we just used head as
an example.
On Wed, Jul 1, 2009 at 5:17 AM, Bogaso<bogaso.christo...@gmail.com>
wrote:
I have a zoo object on daily data for 10 years. Now I want to
create a
list,
wherein each member of that list is the monthly observations. For
example,
1st member of list contains daily observation of 1st month, 2nd
member
contains daily observation of 2nd month etc.
Then for a particular month, I want to divide all observations
into 3
parts
(arbitrary) and then want to calculate some statistics on each
part for
each
month. Therefore for a particular month, I will have 3 means
(suppose,
statistic is mean).
Can anyone throw some light on how to do that?
--
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
______________________________________________
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