try this:
> a
[[1]]
[1] "a" "b" "c"
[[2]]
[1] "d" "e"
[[3]]
[1] "f" "g" "h" "i"
> # find max row length
> rowMax <- max(sapply(a, length))
> # now create output matrix by lengthening rows
> do.call(rbind, lapply(a, function(x){
+ length(x) <- rowMax
+ x
+ }))
[,1] [,2] [,3] [,4]
[1,] "a" "b" "c" NA
[2,] "d" "e" NA NA
[3,] "f" "g" "h" "i"
>
On Mon, Jun 22, 2009 at 7:15 PM, Kenneth Takagi <kat...@psu.edu> wrote:
> Hi,
>
>
>
> I have a list made up of character strings with each item a different
> length (each item is between 1and 6 strings long). Is there a way to
> convert a "ragged" list to a matrix such that each item is its own row?
> Here is a simple example:
>
>
>
> a=list();
>
> a[[1]] = c("a", "b", "c");
>
> a[[2]] = c("d", "e");
>
> a[[3]] = c("f", "g", "h", "i");
>
>
>
> I would like to convert the list to a matrix (or data frame) in this
> form, with the "missing" entries "NA" or something similar:
>
>
>
> [,1] [,2] [,3] [,4]
>
> [1,] "a" "b" "c" "NA"
>
> [2,] "d" "e" "NA" "NA"
>
> [3,] "f" "g" "h" "i"
>
>
>
>
>
> Any suggestions?
>
>
>
> Thanks!
>
>
>
>
>
> Ken
>
> kat...@psu.edu
>
>
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html>
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
[[alternative HTML version deleted]]
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