That is not what his 'for' loops are doing.  He is iterating through all
combinations and would have created 784.  So his problem statement did not
match the code that he sent.

On Thu, Jun 18, 2009 at 2:12 PM, Marc Schwartz <marc_schwa...@me.com> wrote:

> Alexandre did say 28 datasets, not 784 (28 * 28)....
>
> Thus, either:
>
>  mapply(rnorm, n = 500, mean = a1, sd = a2)
>
> or
>
>  apply(cbind(a1, a2), 1, function(x) rnorm(500, x[1], x[2]))
>
>
> HTH,
>
> Marc Schwartz
>
> On Jun 18, 2009, at 12:51 PM, Henrique Dallazuanna wrote:
>
> Try this also:
>>
>> a <- expand.grid(a1, a2)
>> x <- mapply(rnorm, n = 500, mean = a[,1], sd = a[,2])
>>
>> On Thu, Jun 18, 2009 at 2:10 PM, Alexandre Lockhart <
>> alexandre_geor...@hotmail.com> wrote:
>>
>>
>>> Hello:
>>>
>>> My problem is that I have a data frame of means, and a data frame of
>>> standard deviations which match up to each mean.  I have been trying to
>>> create 500 random numbers in a given dataset for each mean/sd
>>> combination,
>>> but I am only able to generate the last value in each data set to create
>>> one
>>> dataset (there should be 28 in all).  Examining my code, what can I
>>> change
>>> to generate 28 datasets based on respective mean and sds?
>>>
>>>
>>>
>>> a1<-c(178.07,178.28,178.08,177.74,177.04,178.17,177.58,57.71,59.6,60.92,59.48,59.32,61.59,59.94,28.9,29.82,30.73,25.68,27.93,28.98,29.76,123.48,127.27,127.8,127.2,127.13,126.71,125.5)
>>>
>>>
>>> a2<-c(1.69,1.3,1,.18,1.53,1.31,1.35,1.83,1.56,1.12,.74,1.48,1.67,1.53,.95,.87,0.03,1.12,1.95,1.22,1.04,1.64,1.83,1,1,1.08,1.35,2.37)
>>> for(i in 1:length(a1))
>>>  for(j in 1:length(a2))
>>>      x<-rnorm(500,mean=a1[i],sd=a2[j])
>>>
>>> Thank you,
>>>
>>> Agl
>>>
>>
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-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?

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