Thank you very much ;)
Jeremiah Rounds wrote:
>
>
> Your error message is because "if" wants a single value and you are giving
> it a vector.
>
>
>
> Typically you want to use functions "all" or any" to correct this error
> message (look them up ?all ?any) and eg if(any(is.na(...))) But in this
> case to accomplish the task you're after I don't even think you want to
> use an if. I am not going to give you precise code because I wasn't able
> to decipher exactly what you were trying to do but something like:
>
>
>
> b[is.na(a)] = 43
>
>
>
> might be helpful. This line would put a 43 in b in the corresponding
> entry that was na in a.
>
>
>
> Good luck!.
>
>
>
>
>
>> Date: Sun, 14 Jun 2009 12:48:58 -0700
>> From: gregori...@gmail.com
>> To: r-help@r-project.org
>> Subject: [R] if + is.na
>>
>>
>> Hello!
>> I wont to use a function is.na()
>>
>> I have two vectors:
>> > a=c(1,NA,3,3,3)
>> > b=c(0,0,0,0,0)
>> and when I use is.na function it's ok:
>> > is.na(a)
>> [1] FALSE TRUE FALSE FALSE FALSE
>>
>> but I would create sth like this:
>>
>> for i in 1:length(a){
>> if (wsp[i] == is.na(a)) {b=43}
>> }
>> or like this
>>
>> if(is.na(a)) b=3 else a
>> [1] 1 NA 3 3 3
>>
>> but I always get an error:
>> the condition has length > 1 and only the first element will be used
>>
>> Could you help me how I may avoid this problem and use function is.na
>> inside
>> function if - else
>> Please
>>
>>
>> --
>> View this message in context:
>> http://www.nabble.com/if-%2B-is.na-tp24025136p24025136.html
>> Sent from the R help mailing list archive at Nabble.com.
>>
>> ______________________________________________
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>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>
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> PLEASE do read the posting guide
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> and provide commented, minimal, self-contained, reproducible code.
>
>
--
View this message in context:
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______________________________________________
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and provide commented, minimal, self-contained, reproducible code.
