Thanks Gabor, this is quite clever and it's nice to see another way of doing
it (without ifelse).
Mark
On Sun, Jun 14, 2009 at 6:51 PM, Gabor Grothendieck <ggrothendi...@gmail.com
> wrote:
> Note that TRUE and FALSE become 1 and 0 when used in arithmetic
> formulae so:
>
> result <- with(DF,
> (type %in% c("A", "B", "C")) *
> (1 * (status == "a") + 2 * (status == "b") + 3 * (status ==
> "c")) +
> (type %in% c("D", "E", "F")) *
> (9 * (status == "a") + 8 * (status == "b") + 7 * (status ==
> "c")))
>
> If none of the conditions hold for row i then result[i] will be 0.
>
>
> On Sun, Jun 14, 2009 at 6:18 PM, Mark Na<mtb...@gmail.com> wrote:
> > Hi,
> > I've been struggling most of the morning with an IF ELSE problem, and I
> > wonder if someone might be able to sort me out.
> >
> > Here's what I need to do (dummy example, my data are more complicated):
> >
> > If type = A or B or C
> > and status = a then count = 1
> > and status = b then count = 2
> > and status = c then count = 3
> >
> > Else if type = D or E or F
> > and status = a then count = 9
> > and status = b then count = 8
> > and status = c then count = 7
> >
> > End
> >
> > Seems simple when I write it like that, but the R code is escaping me.
> >
> > Thanks!
> >
> > Mark Na
> >
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
>
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