Hi friends, Please can anyone help me with an easier solution of doing the below mentioned work. Suppose i have a dataset like this:---
i1 i2 i3 i4 i5 1 7 13 1 2 2 8 14 2 2 3 9 15 3 3 4 10 16 4 4 5 11 17 5 5 6 12 18 6 7 *i1,i2,i3,i4,i5 are my items.I am able to find all possible pairs i.e Say this dataframe is "item_pairs" **i1,i2 **i1,i3 **i1,i4 i1,i5 **i2,i1 **i2,i3 i2,i4 i2,i5 **i3,i1 **i3,i2 **i3,i4 **i3,i5 **i4,i1 **i4,i2 **i4,i3 i4,i5 i5,i1 i5,i2 i5,i3 i5,i4 Pairs like (i1,i1) or (i2,i2) are not required.Now pair (i1,i2) is same as pair (i2,i1) .How can i chop off the second pair which is identicle to the first one,only that sequence of item numbers are different ,otherwise my dataset is same. I thought of something...like ....running loops for all rows and columns of this item_pairs dataframe and check if first item in a pair matches with any second item of previous pair and similarly **second item in a pair matches with any first item of previous pair* and keep entering them in a dataframe and get the unique pairs. But is there any other easier way of chopping off the identicle pairs? *-- * Thanks in advance Moumita [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.