Dear Ruser's
I want to substitute each "NA" by the group mean of which the "NA" is
belonging to. For example, substitute the first record of traits "NA" by the
mean of "BSPy01-10" in the dummy dataframe.
I have ever tried to solve this problem by using doBy package. But, I
failed. I ask for the advice on how to use "lapplyBy" function of "doBy"
package.
The commands used and the output I got are as followed:
library(doBy)
df<-orderBy(~group,data=df) # succeeded
f1<-function(x){m<-mean(x, na.ram=TRUE); x[is.na(x)]<-m; x} # succeeded
datatraits<-lapplyBy(traits~group,data=df, FUN=f1(traits)) # failed
errors: mean(x, na.ram = TRUE), can not find 'traits'.
dummy dataframe:
> df
group traits
1 BSPy01-10 NA
2 BSPy01-10 7.3
3 BSPy01-10 7.3
4 BSPy01-11 5.3
5 BSPy01-11 5.4
6 BSPy01-11 5.6
7 BSPy01-11 NA
8 BSPy01-11 NA
9 BSPy01-11 4.8
10 BSPy01-12 8.1
11 BSPy01-12 6.0
12 BSPy01-12 6.0
13 BSPy01-13 6.1
Thanks in advance.
Sincerely,
Mao J-F
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