Gabor Grothendieck wrote:
> Try this. See ?regex for more.
>
>
>> x <- 'This happened in the 21. century." (the dot behind 21 is'
>> regexpr("(?![0-9]+)[.]", x, perl = TRUE)
>>
> [1] 24
> attr(,"match.length")
> [1] 1
>
yes, but
gregexpr('(?![0-9]+)[.]', 'a. 1. a1.', perl=TRUE)
# 2 5 9
which, i guess, is not what you want. if what you want is to match all
and only dots that follow at least one digit preceded by a word
boundary, then the following should do, as far as i can see:
gregexpr('\\b[0-9]+\\K[.]', 'a. 1. a1.', perl=TRUE)
# 5
vQ
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