Many thanks --- milton ruser <milton.ru...@gmail.com> schrieb am Mo, 8.6.2009:
Von: milton ruser <milton.ru...@gmail.com> Betreff: Re: [R] mean An: "amor Gandhi" <amorigan...@yahoo.de> CC: r-h...@stat.math.ethz.ch Datum: Montag, 8. Juni 2009, 14:27 oops. If x1 is the individual try x2.mean<-aggregate(data[2:2], list(x1), mean) x2.mean you can change "mean" by any function. cheers milton On Mon, Jun 8, 2009 at 8:20 AM, milton ruser <milton.ru...@gmail.com> wrote: Hi Amor, I think you forgot to include the individual ID. ?aggregate cheers milton brazil=toronto On Mon, Jun 8, 2009 at 8:11 AM, amor Gandhi <amorigan...@yahoo.de> wrote: Hi, I have gote the following data x1 <- c(rep(1,6),rep(4,7),rep(6,10)) x2 <- rnorm(length(x1),6,1) data <- data.frame(x1,x2) and I would like to compute the mean of the x2 for each individual of x1, i. e. x1=1,4 and 6? Thank you very much in advance, Amori [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]]
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
