use: sum(x,na.rm=T)
like this: my.row.sums <- apply(my.matrix,1,sum,na.rm=T) If you want to do across columns then use 2 instead of 1. Look at ?apply and ?sum. Adrian On Fri, May 29, 2009 at 7:46 AM, Wade Wall <wade.w...@gmail.com> wrote: > Hi all, > > I have a binary matrix with NAs included. Each row and column > includes at least one NA, so I don't want to omit them. Is there a > way to sum across rows and columns, ignoring the NAs but not deleting > the row or column? If not, I suppose I can write a loop function, but > I have learned that it is best to stay away from loops if possible. > > Thanks for any help, > > Wade > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
