Here are a few ways:
gsub("[+]", "K", "8.00+00")
gsub("\\+", "K", "8.00+00")
gsub("+", "K", "8.00+00", fixed = TRUE)
Note that with gsubfn you can replace several at once as
it is like gsubfn but can take a replacement translation list:
library(gsubfn)
gsubfn(".", list("+" = " plus", "0" = " zero"), "8.00+00")
# gives this: "8. zero zero plus zero zero"
On Thu, May 21, 2009 at 11:45 AM, Tom La Bone <boo...@gforcecable.com> wrote:
>
> I know this is easy, but I am stumped:
>
>> gsub("0","K","8.00+00")
> [1] "8.KK+KK"
>
>> gsub("+","K","8.00+00")
> Error in gsub("+", "K", "8.00+00") : invalid regular expression '+'
> In addition: Warning message:
> In gsub("+", "K", "8.00+00") :
> regcomp error: 'Invalid preceding regular expression'
>
> I don't understand the error message. How do I go about replacing the "+" in
> the string "8.00+00" with another character?
>
> Tom
>
>
>
>
> --
> View this message in context:
> http://www.nabble.com/Replacing-a-%22%2B%22-in-a-string-tp23655515p23655515.html
> Sent from the R help mailing list archive at Nabble.com.
>
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