Hi, you could use which.max(). > fp$Frequenz[which.max(fp$AmpNorm)]
I found the reference in the max() help. Lasse Am Freitag, den 08.05.2009, 14:49 +0200 schrieb Jonas Stein: > Hi, > > fp is a data frame like this > > ,----[ fp ] > | Frequenz AmpNorm > | 1 3322 0.0379490639 > | 2 3061 0.0476033058 > | 3 2833 0.0592954124 > | 4 2242 0.1275510204 > `---- > > i want to find the "Frequenz" where "AmpNorm" is max. > > I use this line as workaround: > PeakFreqHz = subset(fp, AmpNorm == max(AmpNorm))$Frequenz[1] > > Is there something nicer? > And is there an easy way to do the same on "predict()" > > Thank you and kind regards, > -- Lasse Bombien Institut für Phonetik und Sprachverarbeitung Schellingstraße 3/II D-80799 München email: la...@phonetik.uni-muenchen.de web: http://www.phonetik.uni-muenchen.de/~lasse phone: +49 (0) 89 2180 2812 ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
