If Year is numeric data, then you can use: beechworth.dt.2 <- subset(beechworth.dt, Year>=1997 & Year <=2008) If it is character, then you can use: beechworth.dt.2 <- subset(beechworth.dt, Year %in% as.character(1997:2008))
2009/4/20 Roslina Zakaria <zrosl...@yahoo.com>: > > Hi R-users, > > I have a set of data from 1958-2009, how do I extract the data from 1927 and > 2007? > > beechworth.dt > Year Month Rain > 1 1858 3 21.8 > 2 1858 4 47.0 > 3 1858 5 70.1 > 4 1858 6 78.7 > 5 1858 7 101.6 > 6 1858 8 129.8 > 7 1858 9 80.8 > 8 1858 10 41.9 > ... > > 2009 ...... > > > I tried: > > beechworth.dt.2 <- beechworth.dt[beechworth.dt$Year=="1927":"2007",] > > and got > > Warning message: > In beechworth.dt$Year == "1927":"2007" : > longer object length is not a multiple of shorter object length > > Thank you so much for any help given. > > > > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- HUANG Ronggui, Wincent PhD Candidate Dept of Public and Social Administration City University of Hong Kong Home page: http://asrr.r-forge.r-project.org/rghuang.html ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
