Dear Donald,
Assuming that your data is called "mydata", the first column represents the
gender and the questions are the columns left, something like the following
should do the job:
# Some data
set.seed(1)
mydata <- matrix(rbinom(1000,1,p=0.5),ncol=10)
colnames(mydata)<-c('sex',paste('q',1:9,sep=""))
# What you asked -- hopefully ;)
apply(mydata[,-1], 2, tapply, mydata[,1], function(x) sum(x)/nrow(mydata))
HTH,
Jorge
On Tue, Apr 7, 2009 at 4:33 PM, Donald Braman <dbra...@law.gwu.edu> wrote:
> I've been playing around with various table tools, trying to construct a
> fairly simple cross-tab. It shouldn't be hard, but for some reason it
> turning out to be (for me).
>
> If I want to see how many men and how many women agree with a
> agree/disagree
> question (coded 1,0), I can do this:
>
> >attach(mydata)
> >mytable <- table(male, q1.bin) # gender and a binary response variable
> >prop.table(mytable, 1) # row percentages
> q1.bin
> male 0 1
> 0 0.3988 0.6012
> 1 0.2879 0.7121
>
> I can repeat that for each of the items I want gender breakdowns for (q2,
> q3, q4 ....). But what I really want is a table that shows the percentage
> answering yes (coded as 1) across many, many binary response items. E.g.,
>
>
> male q1.bin q2.bin q3.bin ...
> 0 0.6012 0.3421 0.9871 ...
> 1 0.7121 0.6223 0.0198 ...
>
> I've tried various combinations of apply & cbind, but to no avail. It would
> be easy in SPSS crosstabs, but darnit, I want to use R!
>
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>
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