Dear Dimitris, Thanks very much. I tried dim(M) and get: [1] 5030 2142
which I thought meant that my matrix M is actually a matrix, but I tried str(M) and get: int [1:5030, 1:2142] 2 1 2 0 1 0 2 1 2 -1 ... When I tried rowSums(M == 0) I got: Error in rowSums[M == 0] : object of type 'closure' is not subsettable What am I doing wrong? Thanks so much. Dimitris Rizopoulos-4 wrote: > > if 'M' is your matrix, then try this: > > rowSums(M == 0) > > > I hope it helps. > > Best, > Dimitris > > > onyourmark wrote: >> Hi. I have an n x m matrix M some of who's entries are zeros. I want to >> know >> how many zeros there are in each row -perhaps stored in a 1 x n vector >> which lists the number of zeros for each row of M. >> >> Before I had a vector V and I was able to get the number of zeros in V by >> doing length(V[ V==0]) but when I try something similar for M, like M[ >> M==0] >> it creates a vector not a matrix and so this does not work. Does anyone >> have >> a solution to this? >> >> Thank you. > > -- > Dimitris Rizopoulos > Assistant Professor > Department of Biostatistics > Erasmus University Medical Center > > Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands > Tel: +31/(0)10/7043478 > Fax: +31/(0)10/7043014 > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > -- View this message in context: http://www.nabble.com/number-of-zeros-in-a-matrix--row-by-row-tp22893147p22901010.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
