I was suggested to use x = data.frame(string = c( "xxxxx1", "xxxxx2", "yyyyx3")) x
apply(x,1,substr,1,4) and it's worked good! Thank you all Wacek Kusnierczyk wrote: > > calpeda wrote: >> thank you, >> but I m importing data from a txt file and I have a matrix of n*1 >> The function str seems to work only from 1*n >> >> > > you see, it would help if you provided more details from the start. you > may still need to do it; it seems that both solutions you were given > (mine and the substr one) work for both n*1 and 1*n matrices: > > # 5*1 > (strings = matrix(as.character(sample(10^6, 5)), ncol=1)) > > substr(strings, 1, 4) > substr(t(strings), 1, 4) > > with a fixed pattern of four digits from the beginning of the string, > the substr solution is better -- simpler and a few times faster. > > vQ > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > -- View this message in context: http://www.nabble.com/list-substring-tp22826435p22841466.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
