This is probably what you want mydf<-as.data.frame(matrix(1:60,10)) for (i in (1:dim(mydf)[2])) assign(letters[i],mydf[,i])
I would not, however, recommend it. It really does not produce very readable code. emj83 wrote: > I would like to create a series of vectors in a loop and name them with > letters. > > I know the command letters gives me the 26 letters of the alphabet. > > For example, I have a dataframe, called A, with 6 columns. > >> B<-length(A) >> C<-letters(1:B) > [1] "a" "b" "c" "d" "e" "f" > > I would like to extract the first letter "a", and put the first column of > dataframe A in a vector called "a" > >> C<-e[1] > [1] "a" > > but when I type > >> e[1]=A[,1] > > Warning message: > In e[1] =A[, 1] : > number of items to replace is not a multiple of replacement length > > It thinks I am trying to replace the first element of e with the first > column of A. > > is there any other way in which I can achieve this? > > Thanks in advance > > > -- Erich Neuwirth, University of Vienna Faculty of Computer Science Computer Supported Didactics Working Group Visit our SunSITE at http://sunsite.univie.ac.at Phone: +43-1-4277-39464 Fax: +43-1-4277-39459 ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
