Thanks Jorge ,
I mistakingly (and foolishly) confused a vector of ranking, to a vector of
ordering that ranked vector...

Patrick Burns explained to me that I was looking for:
aa[order(aa)]
df[order(df[,1]), ]


Sorry,

Tal




On Sat, Mar 28, 2009 at 9:08 PM, Jorge Ivan Velez
<jorgeivanve...@gmail.com>wrote:

>
> Dear Tal,
> It works as it should. In this code:
>
> # Data
> aa <- c(3, 1 ,2 )
> aa
> [1] 3 1 2
>
> aa[aa]
> [1] 2 3 1
>
> you are telling R to do the following:  take the vector aa and select the
> elements aa (in R language that is aa[aa]). If you look carefully, the third
> element of aa is 2, the first is 3 and the second is 1.
>
> Perhaps I'm missing something but, to me, it works as expected.  What would
> you like to get?
>
> HTH,
>
> Jorge
>
>
> On Sat, Mar 28, 2009 at 1:48 PM, Tal Galili <tal.gal...@gmail.com> wrote:
>
>> Hello people.
>>
>> I wish to reorder a simple vector of numbers by another vector of the
>> order
>> (and then do the same, but with a data frame rows)
>>
>> I try this (which doesn't work) :
>> > aa <- c(3, 1 ,2 )
>> > aa[aa]
>> [1] 2 3 1
>>
>> The same won't work if I try to order a data frame:
>> > data.frame(matrix(c(3,1,2), 3,2))[c(3,1,2),]
>>  X1 X2
>> 3  2  2
>> 1  3  3
>> 2  1  1
>>
>>
>> How should I do this?
>>
>>
>> p.s: sorry if the question is too simple, but I couldn't find a good
>> explanation for this on google.
>> p.p.s: I am running R 2.8
>>
>>
>> Thanks,
>> Tal
>>
>>        [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>


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